Why is this a problem? Isn't the correct way to deal with a sequence lock failure to just retry? A torn read yes means you get undefined behavior as far as the result of your read, but you throw it all away and start again anyway so what is this solving?
A sequence lock is a blocking lock. If the writer dies between the two increment operations, then the readers will spin forever waiting for the counter to become even again.
One of the key operations in these algorithms is a memory copy using core::ptr::copy. However, this results in undefined behavior if one process reads the data while another process writes to it concurrently. Even if our lock-free algorithm reliably detects such a race, iceoryx2 cannot depend on undefined behavior in a safety-critical system. This blog post introduces our solution: a byte-wise atomic wrapper that enables well-defined concurrent copy operations. It also shows how it can be used to implement a simple sequence lock.
I'm also missing any acquire/release barrier annotations in your code snippets. If you're using sequentially consistent accesses you might as well just single thread your code, performance wise.
Lastly, in almost all cases it's way more efficient and appropriate to shuffle things on the whole-object level, posting and retrieving pointers, and not poke around inside objects (especially on the byte level). Check how rare the use of seqlocks in the Linux kernel is, compared to other RCU primitives. (and regarding "appropriate", cf. top-level comment by danbruc https://news.ycombinator.com/item?id=49168283 )