SatoshiGuesser – Roll for Bitcoin(github.com)
47 pointsby ilarum5 hours ago24 comments
  • sunir5 hours ago
    I don't get it. That wasn't hard. What do I do with the key now that I have it?
    • gavmor5 hours ago
      Nothing much, since quantum supremacy will drive all coins to zero, but it is a biohazard.

      Email it to me and I'll safely dispose of it for you at a responsible E-waste site.

    • kibwen4 hours ago
      Same here. I guess "xxxxxxxxxxxxxxxxxxxxxxxxxxxxx12345" made it easy for Satoshi to remember, though.
    • soperj5 hours ago
      Post it on here. We'll all help you out.
    • dudeinjapan5 hours ago
      The honest thing to do is to return the key you found to its owner Satoshi Nakamoto.
  • curiousObject4 hours ago
    >At one spin per millisecond (faster than this app runs), you'd expect a hit roughly once per 1.7 × 10⁶² years — about 10⁵² times the current age of the universe. The heat death of the universe occurs first

    Alright! Now there’s only the heat death of the universe standing between me and massive wealth? I like these odds.

    • gumgumpostan hour ago
      Those are just the odds, but you randomly finding it in the next 10 minutes is a valid move in this universe. The silly low odds don't guarantee you won't find it.
  • meowface4 hours ago
    I'm not opposed to LLM-generated code at all, but the such obviously LLM-written README is annoying. The style is so easy to spot. At least try to figure out how to prompt it to not write so obviously like an LLM. (And no, I'm not even referring to the em dashes.)
    • futune3 hours ago
      Why would you want LLM content to masquarade as non-LLM content? I think I'd rather have it be obvious if people are going to be using it anyway.
      • bpavuk3 hours ago
        ignorance is bliss. all LLM text reads same-y. that way, we at least have an illusion that this is not a LLM
  • sunrunner5 hours ago
    99% of gamblers quit before they win big. In this case, really big. I am going to be the 1%. Or should that be the 1.9e-71%.
    • ck453 hours ago
      You either win or you don’t, it’s 50:50
  • int32_645 hours ago
    A better project would be to take the exact key generation function at the time Satoshi started it and mine possible PRNG parameters.
  • amarant4 hours ago
    I dunno if I'm missing something, but I can't see the actual guessed key anywhere on the site?

    So if I win, I won't be able to actually claim the Mooney's?

    • Hakkin4 hours ago
      The key shows up if you win, you can simulate it by adding ?devwin=1 to the URL.
      • amarant4 hours ago
        Oh. That makes sense I guess.

        I don't think it'll ever show for reals

  • opengrass5 hours ago
    There's also the Large Bitcoin Collider. Last time coins were recovered was 9 years ago. https://lbc.cryptoguru.org/about
  • FajitaNachos5 hours ago
    I made a similar concept, but it wasn't self hosted. I never made the front page though! Congrats. Could you add a video of the experience to GitHub. Without that I wasn't willing to download and give it a go
  • CobrastanJorji5 hours ago
    What's really fun is that, if you win and do anything about it, Bitcoin's value immediately crashes.
    • felooboolooomba4 hours ago
      Yes, but I think it'll back up within a year. It's crazy.
  • ex-aws-dude4 hours ago
    Question is does the dev sneak in some secret notification code if someone hits it?
    • aqme284 hours ago
      No reason to--no one will hit. You have much much much chance at guessing a random number that solves the next bitcoin block and mining the old fashioned way.
  • starkeeper4 hours ago
    So is this a door-knocking bitcoin robbery game?
  • runj__4 hours ago
    I got a couple of hits by pressing command-R _really_, _really_ fast. But transferring from Nakamoto's wallet feels a bit like fucking with the first bootprints in the lunar regolith.
  • MattCruikshank4 hours ago
    Quick question - why hasn't someone 51 percent attacked Satoshi's wallets?

    Estimated cost of a 51% attack on Bitcoin, if no one is cooperating, is $6 billion to $10 billion.

    Surely the cost goes down if they get some big players to cooperate.

    And the reward is... $83 billion. Basically 10x your money.

    I mean, this is the kind of thing that we could sell bonds for, to raise the $6 to $10 billion needed.

    Other than the fact that you'd be de-legitimizing BTC, the very thing you're trying to steal. Or morals - them, too. Other than that?

    • pawelduda3 hours ago
      Once these coins as much as budge, price will crater before the transaction has enough confirmations to settle the deposit on any exchange with enough liquidity. Any second on exchange and the hacker is exposed to having his account frozen.

      Nobody would buy OTC as they're tainted and it would be basically throwing away their money for something that is traceable and everyone is watching and reacting to further moves

      Then the blockchain could be effectively forked to before the attack, invalidating the heist

    • sanswork4 hours ago
      51% attack on bitcoin doesn't let you remove coins from someones wallet it allows you to change which transaction history is considered the real one. So you could send someone bitcoin then do a 51% attack to make the chain without that transaction longest so you get to keep your bitcoin but you can't use it to just take money out of someone elses wallet.
    • curiousObject4 hours ago
      51% attack allows you to undo a recent transaction (as if it never happened). It does not allow you to change the destination of a transaction or arbitrarily move bitcoins around.
    • 4 hours ago
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  • zikduruqe5 hours ago
    https://keys.lol is just as fun.
  • sciencesama5 hours ago
    can use collaborated list to remove the random numbers that failed already.
    • ivanjermakov5 hours ago
      That's gonna be a nice storage bill!
      • CobrastanJorji4 hours ago
        Let's see...2^241 or so possible 256 bit numbers, so that's 256 * 2^241, so that's....10^50 yottabytes. Obviously we're gonna need cloud storage for all this, so let's say that's about 2 cents per gigabyte/month, so that's...2.2614 × 10^63 dollars per month?

        Actually, why does the site list the odds as ~1 in 5.27 × 10⁷²? That's 2^241, but it's picking random 256 bit numbers. Is it because there are so many valid hits?

        • gumgumpostan hour ago
          Since you're at it, if you're also curious, what would be the energy cost of trying all of them, considering the average power used by a random computer today? Are we looking at something like an average quasar total contained energy?
  • logicallee5 hours ago
    This is really fun, I like it a lot. It's great that it's all client-side, real, and does exactly what it says.
  • fred_is_fred3 hours ago
    If you actually won this amount of money it would effectively ruin your life. You and your family would never be safe from a wrench attack - from criminals or a nation-state.
  • fred_is_fred3 hours ago
    Is the search space too big to effectively divide it up GIMPS-style. How do the odds look if every laptop on earth was trying this?
  • SilentM684 hours ago
    Hmm, maybe this can help me win the Monopoly Lottery :)
  • m3kw95 hours ago
    Why wouldn't the host just send themselves the key first and then have everyone pull slot machine for them. If you do win it, you are not seeing a penny if you roll from that site.
    • rokkamokka5 hours ago
      There's no realistic chance it'll be correct anyway
      • sunrunner5 hours ago
        Not with that attitude it won’t
    • FajitaNachos5 hours ago
      Generally agree that most services like this would at a minimum log a matching key w/ alert. I'm not going to audit the code but maybe OP has good intentions.
  • 5 hours ago
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  • jan_Sate5 hours ago
    lol. It's fun. Not that I could ever guess it right realistically but it's fun.

    This kind of fun thing's exactly why I'm on the internet. Thanks for sharing! :D

  • m3kw95 hours ago
    what does it mean Loaded 21954 wallets ?
  • m3kw95 hours ago
    maybe some quantum algo can guess every key at once.