SET = []; INTERVAL = []; SUMMA = 0; PRODUCT = 1;
def set_(line): global SET SET = list(map(int, line[1:-1].split(', '))) print(SET)
def interval_(line): global INTERVAL, SUMMA, PRODUCT interval, iterator, expression = line.split(' ') match interval[0]: case '(': l = int(interval[1])+1 case '[': l = int(interval[1]) match interval[-1]: case ')': r = int(interval[-2]) case ']': r = int(interval[-2])+1 INTERVAL = list(range(l, r)) if iterator: match iterator[0]: case 'A': for i in INTERVAL: SUMMA += SET[i] print(SUMMA) case 'P': for i in INTERVAL: PRODUCT = SET[i] print(PRODUCT)
def comment_(line): if line != '""': print(line) if line[-1] == '"': print()
def parse(line): match line[0]: case '"': comment_(line) case '{': set_(line) case '(' | '[': interval_(line) case 'I': print(sum([s*s for s in [e+sum(SET) for e in SET]])) # :-( case _: print(f'ERROR {line}')
def scan(f): for line in f: line = line.strip() if line: parse(line)
if __name__ == '__main__': f = open(sys.argv[1]); scan(f) f.close() ---------------------------------------------------- RESULT -------------------------------------------------- python ladder.py program.l "ladder - interpreted programming language" "this is a set (S) 1 2 3 4 5 "this is an amount (A) of the set (S) with an interval (I) 15 "this is the product (P) of the sum of the "elements of the set (S) and an amount (A) of the set (S) "with an interval (I) 1630
how is this remotely possible? as Claude Code codebase was very large.