59 pointsby mpweihera month ago7 comments
  • rm445a month ago
    I've read this book. It's definitely one of the more interesting and readable maths texts out there. I wasn't exactly sure I'd use the methods. Working as a mechanical engineer I probably go straight to numerical methods, or approximate things even more crudely and approximately than a mathematician's 'rough' work. Though "replace a complicated function with a rectangle" definitely resonated. Overall the impression was that it was full of great techniques for mathematicians and scientists puzzling out every bit of meaning they can from a situation whose true features aren't yet known.
    • ErroneousBosha month ago
      That's kind of how I do maths, too. Working out the lengths of antenna feeders, for example, where a coil of cable is about 30cm across. One turn of that is about one metre, so a coil with ten turns is about ten metres. Roughly. Close enough. I can coil it up shorter but I can't coil it up longer.

      If I'm doing really precise stuff, I'm either doing it on a computer already or it's something that's just going to have to be "adjusted" into place when it's done.

      In high school my maths teacher said "You'll need to learn all this, you won't always have a calculator!"

      My dude, I am walking around with a supercomputer the size of half a slice of bread in my pocket, that probably has a sizeable fraction of the total computing power available in the world when you told me that.

      It turns out I don't need either of these things, I just need a good sense of "yeah that feels about right".

      • stefanfiska month ago
        Not to mention instant and searchable access to more subject matter than he’d seen in his whole lifetime.
  • nutjob2a month ago
    • marcia month ago
      This is the draft, not the current version.

      edit: and for the current unfortunately there's only a dead dropbox link.

  • stmwa month ago
    This is a good book. Also, any time this kind of book becomes available (be it a 100 year old one or a new one), it is worth looking into - great improvements in isnight and simplicity are possible above the "baseline" of US math education today.

    So for example, I posit that the engineers or scientists you might admire from the 1950's didn't learn calculus or linear algebra the way you did.

    • gpcza month ago
      Feynman learned calculus from the textbook "Calculus for the Practical Man".
  • brennanpetersona month ago
    I also quite liked https://ocw.mit.edu/courses/res-6-011-the-art-of-insight-in-...

    Which is, I think, the successor and quite useful.

  • jesuslopa month ago
    I skimmed the chapter on operators (7) and always liked that way of thinking (plug things like the derivative operation D into things that expect numbers instead, and see what happens). So plugging into 1/x and getting integrals. Dattoli and Tom Copeland do serious stuff starting from that kind of considerations that go way beyond cocktail party tricks.
  • groundzeros2015a month ago
    Another book title aimed at getting people who haven’t read their pile of books to buy another.
  • NooneAtAll3a month ago
    what is it about?

    how to distribute fighters so that your team defeats-in-detail your opponents?

    • slow_typista month ago
      It is about useful tricks you can usually not learn in university classes.
      • NooneAtAll3a month ago
        tricks of what kind
        • wolfi1a month ago
          fast multiplying for example
          • slow_typista month ago
            Also how to make good estimates, and how to work with units.

            One example, the formula to get the speed of a thing after h meters of free fall must deliver an outcome of m/s. We also know the gravitational acceleration g is given in m/s^2. Then, height h in m must somehow be part of the formula. We can get rid of the squaresecond in the denominator by drawing the square root. But then we also need the height in meters. Also it is clear that both more height as well as a higher acceleration must lead to higher speed. Therefore, the speed must be proportional to sqrt(h x g). In fact it is v = 1/2 sqrt(h x g) but we can derive the important part only from knowing how to calculate with units.